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MTH603 - Numerical Analysis

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  • decimal fractions

    decimal fractions binary system represented in binary system
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    zaasmiZ
    @engr-ali said in decimal fractions: Assallamulikum Sir, Conversion (59)10 into binary 59/2=28-1 ? 28/2=14-0 14/2=7-0 7/2=3-1 3/2=1-1 (111001) ? Dear @Engr-Ali , $(59){10} = (111011){2}$ The mistake you have made is in the first step where you divided $59/2$. It has to be $29-1$ instead of $28-1$. Best wishes
  • Errors in Computations.

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    zaasmiZ
    @vu-kick said in Errors in Computations.: What is synchronous and asynchronous and what are there applications in real world. Which applications use this sort of techniques. The word synchronous and asynchronous are very general terms that are used in different fiels representing different phenonena. If you can please ask it more clearly that in what context you are asking. It will be good if you please mention what page of handouts, what slide of ppts or where in the lecture video of the numerical analysis you studied/heard about it. Then we’ll be able to explain it well. Best wishes
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    zaasmiZ
    @oxama-malik said in Solution of Non Linear Equations (Bisection Method): respected sir, sir ma na ye pochna tha ka regula falsi method ma hum ye bhi formula use kar sakta hai. please guide kar dya. the first approximation solution x1 is given by X1=(a(f(b))-b(f(a))/f(b)-f(a) That is right. You can use this formula. In fact, the formula given in the handouts becomes same after you simplify it. Also $x_{n-1}$ will become $a$ and $x_{n}$ will become $b$. So use any from the two formulas you find easier. Best wishes
  • replace the part of curve between the points

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    E
    @engr-ali said in replace the part of curve between the points: AoA, Sir if you may plz explain “replace the part of curve between the points A(x_n, f(x_n)) and B(x_n-1, f(x_n-1)) by a chord in the interval” . diagrammatic explanation will be a great help in comprehension of the subject matter. Thanks A chord is basically a straight line by joining two points of a curve or circle. The root of a equation means that when we give input value x then the functional value of that input will be zero then x is called the root of that equation. We take the two points of the interval on the chord instead of the curve shape because the value of root lies in that interval and this mean this value will lie on x-axis and if this is the root then functional value will be zero and we know that y-axis (functional value) is zero at x-axis.
  • MTH603 Quiz 2 Solution and Discussion

    mth603 quiz 2 solution discussion fall 2019
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    zaasmiZ
    @zainab-ayub said in MTH603 Quiz 2 Solution and Discussion: Mth603 ka koi student hai tu plz yeh question bta dy kis trha solve ho ga Given the following data x:1 2 5 y:1 4 10 Value of 1st order divided difference f[2 , 5] is [image: JgeUzkI.png]
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    zaasmiZ
    @zareen said in MTH603 Assignment 1 Solution and Discussion: Question #2: Solve the system of linear equations with the help of Gaussian elimination method. 2x + y + z = 9;3x −2y + 4z = 9;x +y-2z = 3 System of Linear Equations entered : [1] 2x + y + z = 9 [2] 3x - 2y + 4z = 9 [3] x + y - 2z = 3 Solve by Substitution : // Solve equation [3] for the variable y [3] y = -x + 2z + 3 // Plug this in for variable y in equation [1] [1] 2x + (-x +2z+3) + z = 9 [1] x + 3z = 6 // Plug this in for variable y in equation [2] [2] 3x - 2•(-x +2z+3) + 4z = 9 [2] 5x = 15 // Solve equation [2] for the variable x [2] 5x = 15 [2] x = 3 // Plug this in for variable x in equation [1] [1] (3) + 3z = 6 [1] 3z = 3 // Solve equation [1] for the variable z [1] 3z = 3 [1] z = 1 // By now we know this much : x = 3 y = -x+2z+3 z = 1 // Use the x and z values to solve for y y = -(3)+2(1)+3 = 2 Solution : {x,y,z} = {3,2,1}
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    No one has replied
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    zaasmiZ
    MTH603 MCQ’s for Final Term.pdf
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    zaasmiZ
    Solution idea
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    cyberianC
    https://youtu.be/tQRwrupC2Ao Spring 2020_MTH603_1_SOL.docx
  • MTH603 Assignment 1 Solution and Discussion

    Solved mth603 assignment 1 solution discussion fall 2019
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    zareenZ
    Assignment No: 01 Question #1: Find the root of the equation, Perform three iteration of the equation, ln (x −1) + sinx =0 by using Newton Raphson method. Ans: Let f(x) = ln(x+1) + sinx = 0 and f(x) = 1/(x-1) + cosx F (1.5) = ln(0.5) + (1.5) = - 0.0667 F(2) = ln(1) + sin(2) = 0.035 Since f (1.5) f (2) < 0 so roots lies in interval [1.5, 2] Let x0 = 1.75 . x0 can be taken in the interval any real number [ 1.5 , 2 ], we let mid point of this interval . As we know Newton Raphson method is Xn+1 = xn – f ( xn ) / f(xn) First iteration X1 = x0 –f(x0) / f(x0) = 1.75 - f(1.75) / f(1.75) = 1.75 – (-0.2571 / 2.3329) = 1.8602 Second iteration: X2 = x1 - f(x) / f(x) = 1.8602 –[ f(1.8602) / f(1.8602)] = 1.8602 - ( -0.1181 / 2.1620 ) = 1.9148 Third iteration: X3 = x2- f(x2) / f(x2) = 1.9148 –f(1.9148) / f(1.9148) = 1.9148 – [-0.0556/2.0926] = 1.9414 Question #2: Solve the system of linear equations with the help of Gaussian elimination method. x + y + z = 6;2x − y + z = 3;x + z = 4 ANS: In Gaussian elimination method we convert the augmented matrix into reduce Echelon form therefore, Augmented matrix is R2- 2R1 , R3 – R1 -1R2 , -1R3 R23 R3-3R2 X + Y+ Z = 6 ;………………….(1) Y = 2, Z = 3 Put into eq (1), we get X = 1 ,
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