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    mgt411 assignment 1 solutions 2021 spring.docx
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    zareenZ
    @triggered-man said in assignment 1: Assignment No. 1 (Lectures # 1 to 9) Total Marks: 10 Spring 2021 Discrete Mathematics (MTH202) Due Date: 20-05- 2021 Please read the following instructions before attempting the solution of this assignment: To solve this assignment, you should have good command over 1 to 9 lectures. Try to consolidate your concepts that you learn in the lectures with these questions. Upload assignments properly through VULMS. No Assignment will be accepted through Email. No assignment will be accepted after the due date. Write your ID on the top of your solution file. All students are directed to use the font and style of text as is used in this document. Use MathType or Equation Editor etc. for mathematical symbols and equations. Remember that you are supposed to submit your assignment in MS-Word format any other format like scanned, images, MS-Excel, HTML etc. will not be accepted. Do not use colorful backgrounds in your solution files. This is an individual assignment (not a group assignment). So keep in mind that you are supposed to submit your own, self-made and different assignment even if you discuss the questions with your class fellows. All similar assignments (even with some meaningless modifications) will be awarded zero marks and no excuse will be accepted. This is your responsibility to keep your assignment safe from others. Question No.1 Marks: 10 Let the universal set U be the set of integers and A={x∈Z|0<x≤5} and B={x∈Z|3≤x<9}, then find 〖(A∪B)〗^c 〖(A∩B)〗^c [image: BiuGXKe.png]
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    Sample Output A1 Sample Output.mp4
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    reeloraR
    @zareen said in PHY101 GDB 1 Solution and Discussion: It is true or wrong that Raise For Success an automobile at rest can be accelerating very fast?
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    cyberianC
    Q.2 Solution: Method 1 [image: jCrQeLM.png] Method 2 [image: rHiXB61.png] [image: k84qIO4.png]
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    cyberianC
    @asad-saab Fall 2023 MTH603 Assignment # 1 Section In charge: Husna Muzaffar Total Marks 20 Instructions To solve this assignment you need to have a good grip on lectures 1-15. The course is segmented into four sections, each of which is supervised by a different faculty member. Information regarding the section in charge can be found in the course information section on the LMS. A distinct assignment file has been given to each section, resulting in a total of four separate assignment files. The relevant assignment file can be downloaded from the announcement section of the course. It is important to note that students can only view the announcements relevant to their respective sections. You will prepare the solution of assignment on Word file and upload at the assignment interface on LMS as per usual practice. Plagiarism in the submitted assignment will lead to a zero grade. Additionally, any student who submits a solution file that is not applicable to their section will also get a zero grade. 𝐐𝐮𝐞𝐬𝐭𝐢𝐨𝐧# 𝟏: Marks 10 Solve the system of equations by using Crout’s method. 2𝑥 + 5𝑦 + 3𝑧 = 16 𝐐𝐮𝐞𝐬𝐭𝐢𝐨𝐧# 𝟐: Marks 10 3𝑥 + 𝑦 + 2𝑧 = 11 −3𝑥 + 7𝑦 + 8𝑧 = 10 Solve the following system of equations by using Jacobi′s iterative method for the first three iterations by taking initial starting of solution vector as (0,0,0). 8𝑥 − 2𝑦 − 2𝑧 = 3 −2𝑥 + 6𝑦 + 𝑧 = 9 −2𝑥+𝑦+7𝑧= 6 [center][image: wNTUZAq.png][/center]
  • What is the Key summery of 8601 ?

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    zaasmiZ
    // CS201 Assignment 2 Solution Spring 2021 #include <iostream> #include <conio.h> using namespace std; int ShowMatrix() { //main matrix int row=2, column=2; int matrix[2][2] = { {8, -4} , {-6, 2} }; cout<<"The matrix is:"<<endl; for(int i=0; i<row; ++i) { for(int j=0; j<column; ++j) cout<<matrix[i][j]<<" "; cout<<endl; } } //Transpose int showTranspose ( ) { int transpose[2][2], row=2, column=2, i, j; int matrix[2][2] = { {8, -4} , {-6, 2} }; cout<<endl; for(i=0; i<row; ++i) for(j=0; j<column; ++j) { transpose[j][i] = matrix[i][j]; } cout<<"The transpose of the matrix is:"<<endl; for(i=0; i<column; ++i) { for(j=0; j<row; ++j) cout<<transpose[i][j]<<" "; cout<<endl; } } //determenent calculating int calculateDeterminant() { int determMatrix[2][2], determinant; int matrix[2][2] = { {8, -4} , {-6, 2} }; determinant = ((matrix[0][0] * matrix[1][1]) - (matrix[0][1] * matrix[1][0])); cout << "\nThe Determinant of 2 * 2 Matrix = " << determinant; } //Adjoint of matrix int showAdjoint() { int ch,A2[2][2] = {{8,-4},{-6,2}},AD2[2][2],C2[2][2]; //Calculating co-factors of matrix of order 2x2 C2[0][0]=A2[1][1]; C2[0][1]=-A2[1][0]; C2[1][0]=-A2[0][1]; C2[1][1]=A2[0][0]; //calculating ad-joint of matrix of order 2x2 AD2[0][0]=C2[0][0]; AD2[0][1]=C2[1][0]; AD2[1][0]=C2[0][1]; AD2[1][1]=C2[1][1]; cout<<"\n\nAdjoint of A is :- \n\n"; cout<<"|\t"<<AD2[0][0]<<"\t"<<AD2[0][1]<<"\t|\n|\t"<<AD2[1][0]<<"\t"<<AD2[1][1]<<"\t|\n"; } int main() { int cho = 0; cout<<" ||---Enter your choice---||"<<endl; cout<<""<<endl; cout<<"---Press 1 to display the matrix and its transpose---"<<endl; cout<<"---Press 2 to find adjoint and determinant of the matrix---"<<endl; cout<<""<<endl; cout<<"Press any other key to exit."; cout<<""<<endl; cin>>cho; if (cho ==1) { ShowMatrix(); showTranspose ( ); } else if (cho == 2) { showAdjoint(); calculateDeterminant(); } else system("pause"); }
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    https://youtu.be/GIQRKwKoxHk
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    Aqib JavaidA
    @zaasmi said in MGT301 GDB 1 Solution and Discussion: Re: MGT301 GDB 1 Solution and Discussion MGT301 GDB NO.1 2020 Digital payment services such as internet banking and mobile phone banking, hard cash continues to be avoided as it is considered to be one of the carriers of this virus. To further control the spread, as well as with the systematic shutdown of public dealing, it became inevitable for banks and other financial institutions to go digital entirely. Providing them with a digital tool that not only lets them track their financial transactions, but also sorts them in terms of priority and notifies them when to put their spending on hold could help customers better understand their financial standing. It’s just idea solution kindly make your GDB own your wording don’t submit same GDB.
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