Skip to content

MTH603 - Numerical Analysis

4 Topics 728 Posts
  • 0 Votes
    6 Posts
    2k Views
    cyberianC
    @asad-saab Fall 2023 MTH603 Assignment # 1 Section In charge: Husna Muzaffar Total Marks 20 Instructions To solve this assignment you need to have a good grip on lectures 1-15. The course is segmented into four sections, each of which is supervised by a different faculty member. Information regarding the section in charge can be found in the course information section on the LMS. A distinct assignment file has been given to each section, resulting in a total of four separate assignment files. The relevant assignment file can be downloaded from the announcement section of the course. It is important to note that students can only view the announcements relevant to their respective sections. You will prepare the solution of assignment on Word file and upload at the assignment interface on LMS as per usual practice. Plagiarism in the submitted assignment will lead to a zero grade. Additionally, any student who submits a solution file that is not applicable to their section will also get a zero grade. 𝐐𝐮𝐞𝐬𝐭𝐢𝐨𝐧# 𝟏: Marks 10 Solve the system of equations by using Crout’s method. 2𝑥 + 5𝑦 + 3𝑧 = 16 𝐐𝐮𝐞𝐬𝐭𝐢𝐨𝐧# 𝟐: Marks 10 3𝑥 + 𝑦 + 2𝑧 = 11 −3𝑥 + 7𝑦 + 8𝑧 = 10 Solve the following system of equations by using Jacobi′s iterative method for the first three iterations by taking initial starting of solution vector as (0,0,0). 8𝑥 − 2𝑦 − 2𝑧 = 3 −2𝑥 + 6𝑦 + 𝑧 = 9 −2𝑥+𝑦+7𝑧= 6 [center][image: wNTUZAq.png][/center]
  • 0 Votes
    3 Posts
    2k Views
    zaasmiZ
    @zareen said in MTH603 Assignment 1 Solution and Discussion: Question #2: Solve the system of linear equations with the help of Gaussian elimination method. 2x + y + z = 9;3x −2y + 4z = 9;x +y-2z = 3 System of Linear Equations entered : [1] 2x + y + z = 9 [2] 3x - 2y + 4z = 9 [3] x + y - 2z = 3 Solve by Substitution : // Solve equation [3] for the variable y [3] y = -x + 2z + 3 // Plug this in for variable y in equation [1] [1] 2x + (-x +2z+3) + z = 9 [1] x + 3z = 6 // Plug this in for variable y in equation [2] [2] 3x - 2•(-x +2z+3) + 4z = 9 [2] 5x = 15 // Solve equation [2] for the variable x [2] 5x = 15 [2] x = 3 // Plug this in for variable x in equation [1] [1] (3) + 3z = 6 [1] 3z = 3 // Solve equation [1] for the variable z [1] 3z = 3 [1] z = 1 // By now we know this much : x = 3 y = -x+2z+3 z = 1 // Use the x and z values to solve for y y = -(3)+2(1)+3 = 2 Solution : {x,y,z} = {3,2,1}
  • 0 Votes
    3 Posts
    3k Views
    cyberianC
    https://youtu.be/tQRwrupC2Ao Spring 2020_MTH603_1_SOL.docx
  • MTH603 Assignment 1 Solution and Discussion

    Solved mth603 assignment 1 solution discussion fall 2019
    4
    0 Votes
    4 Posts
    1k Views
    zareenZ
    Assignment No: 01 Question #1: Find the root of the equation, Perform three iteration of the equation, ln (x −1) + sinx =0 by using Newton Raphson method. Ans: Let f(x) = ln(x+1) + sinx = 0 and f(x) = 1/(x-1) + cosx F (1.5) = ln(0.5) + (1.5) = - 0.0667 F(2) = ln(1) + sin(2) = 0.035 Since f (1.5) f (2) < 0 so roots lies in interval [1.5, 2] Let x0 = 1.75 . x0 can be taken in the interval any real number [ 1.5 , 2 ], we let mid point of this interval . As we know Newton Raphson method is Xn+1 = xn – f ( xn ) / f(xn) First iteration X1 = x0 –f(x0) / f(x0) = 1.75 - f(1.75) / f(1.75) = 1.75 – (-0.2571 / 2.3329) = 1.8602 Second iteration: X2 = x1 - f(x) / f(x) = 1.8602 –[ f(1.8602) / f(1.8602)] = 1.8602 - ( -0.1181 / 2.1620 ) = 1.9148 Third iteration: X3 = x2- f(x2) / f(x2) = 1.9148 –f(1.9148) / f(1.9148) = 1.9148 – [-0.0556/2.0926] = 1.9414 Question #2: Solve the system of linear equations with the help of Gaussian elimination method. x + y + z = 6;2x − y + z = 3;x + z = 4 ANS: In Gaussian elimination method we convert the augmented matrix into reduce Echelon form therefore, Augmented matrix is R2- 2R1 , R3 – R1 -1R2 , -1R3 R23 R3-3R2 X + Y+ Z = 6 ;………………….(1) Y = 2, Z = 3 Put into eq (1), we get X = 1 ,
How to Build a $1,000/Month PAK VS BAN Live Live Cricket Streaming
File Sharing

1

Online

3.0k

Users

2.8k

Topics

8.2k

Posts
| |