MTH603 Mid Term Past and Current Solved Paper Discussion
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If the root of the given equation lies between a and b, then the first approximation to the root of the
equation by bisection method is …►
( )
2
a b
Page 9►
( )
2
a b ►
( )
2
b a
► None of the given choices@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
If the root of the given equation lies between a and b, then the first approximation to the root of the
equation by bisection method is …►
( )
2
a b
Page 9►
( )
2
a b ►
( )
2
b a
► None of the given choicesIn the bisection method, the first approximation to the root of the equation, given that the root lies between ( a ) and ( b ), is calculated as the midpoint of the interval ([a, b]). This is done to refine the interval where the root lies.
The formula for the midpoint is:
[ \frac{a + b}{2} ]
So, the correct choice is:
(\frac{a + b}{2})
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To apply Simpson’s 3/8 rule, the number of intervals in the following must be
► 10
► 11
► 12
► 13 -
To apply Simpson’s 3/8 rule, the number of intervals in the following must be
► 10
► 11
► 12
► 13@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
To apply Simpson’s 3/8 rule, the number of intervals in the following must be
► 10
► 11
► 12
► 13Simpson’s 3/8 rule requires that the number of intervals ( n ) be a multiple of 3. This is because the 3/8 rule is based on approximating the integral of a function using a cubic polynomial, which necessitates the intervals being divisible by 3 for proper application.
To apply Simpson’s 3/8 rule correctly, the number of intervals ( n ) must satisfy:
[ n = 3k ]
where ( k ) is a positive integer.
Given the options:
- 10 (not a multiple of 3)
- 11 (not a multiple of 3)
- 12 (multiple of 3, since ( 12 = 3 \times 4 ))
- 13 (not a multiple of 3)
The correct choice is:
12
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The Gauss-Seidel method is applicable to strictly diagonally dominant or symmetric________ definite
matrices A.
Select correct option:
Positive
negative -
The Gauss-Seidel method is applicable to strictly diagonally dominant or symmetric________ definite
matrices A.
Select correct option:
Positive
negative@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
The Gauss-Seidel method is applicable to strictly diagonally dominant or symmetric________ definite
matrices A.
Select correct option:
Positive
negativeThe Gauss-Seidel method is typically applicable to strictly diagonally dominant or symmetric positive definite matrices ( A ).
Explanation:
-
Strictly Diagonally Dominant Matrices: The Gauss-Seidel method converges for strictly diagonally dominant matrices, which ensures that the diagonal elements are sufficiently large compared to the sum of the other elements in the row.
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Symmetric Positive Definite Matrices: For symmetric positive definite matrices, the Gauss-Seidel method is also guaranteed to converge. Positive definiteness ensures that the matrix has a unique solution and the method will converge.
Thus, the correct option is:
Positive
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Differences methods find the ________ solution of the system.
Select correct option:
numerical
Analytical -
Differences methods find the ________ solution of the system.
Select correct option:
numerical
Analytical@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
Differences methods find the ________ solution of the system.
Select correct option:
numerical
AnalyticalDifference methods (such as finite difference methods) are used to find the numerical solution of systems of differential equations or partial differential equations.
Explanation:
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Numerical Solution: Difference methods approximate solutions to problems by discretizing the equations and solving them numerically. These methods are used when exact analytical solutions are difficult or impossible to obtain.
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Analytical Solution: Analytical methods seek exact solutions through algebraic manipulations and typically involve solving equations in their exact forms.
Thus, the correct option is:
numerical
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To apply Simpson’s 1/3 rule, the number of intervals in the following must be
► 2 (Simpson’‘s 1/3 rule must use an even number of elements’)
► 3
► 5
► 7 -
To apply Simpson’s 1/3 rule, the number of intervals in the following must be
► 2 (Simpson’‘s 1/3 rule must use an even number of elements’)
► 3
► 5
► 7@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
To apply Simpson’s 1/3 rule, the number of intervals in the following must be
► 2 (Simpson’‘s 1/3 rule must use an even number of elements’)
► 3
► 5
► 7To apply Simpson’s 1/3 rule, the number of intervals ( n ) must be an even number. This is because Simpson’s 1/3 rule requires that the interval be divided into an even number of subintervals for proper application, as the rule is based on approximating the integral of a function using quadratic polynomials over pairs of subintervals.
Explanation:
- Simpson’s 1/3 Rule: This rule applies to cases where the number of intervals is even, ensuring that each pair of intervals is approximated by a quadratic polynomial.
Given the options:
- 2 (even number, so it’s valid for Simpson’s 1/3 rule)
- 3 (odd number, not valid)
- 5 (odd number, not valid)
- 7 (odd number, not valid)
The correct choice is:
2
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Bisection and false position methods are also known as bracketing method and are
always
Divergent
Convergent -
Bisection and false position methods are also known as bracketing method and are
always
Divergent
Convergent@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
Bisection and false position methods are also known as bracketing method and are
always
Divergent
ConvergentBisection and false position methods (Regula Falsi) are known as bracketing methods. They are convergent methods.
Explanation:
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Bisection Method: This method always converges to a root if the function is continuous and if the initial interval ([a, b]) contains a root (i.e., ( f(a) \cdot f(b) < 0 )). It works by iteratively narrowing down the interval where the root lies.
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False Position Method (Regula Falsi): This method also converges to a root under similar conditions. It improves on the interval using linear interpolation to approximate the root.
Both methods guarantee convergence to a root as long as the initial conditions are satisfied (the function changes sign over the interval).
Thus, the correct option is:
Convergent
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The Inverse of a matrix can only be found if the matrix is
Singular
None Singular: Every square non-singular matrix will have an inverse.
Scalar
Diagonal -
The Inverse of a matrix can only be found if the matrix is
Singular
None Singular: Every square non-singular matrix will have an inverse.
Scalar
Diagonal@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
The Inverse of a matrix can only be found if the matrix is
Singular
None Singular: Every square non-singular matrix will have an inverse.
Scalar
DiagonalThe inverse of a matrix can only be found if the matrix is:
None Singular: Every square non-singular matrix will have an inverse.
Explanation:
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Singular Matrix: A matrix that does not have an inverse. A matrix is singular if its determinant is zero.
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Non-Singular Matrix: A matrix that has an inverse. A matrix is non-singular if its determinant is non-zero.
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Scalar Matrix: A diagonal matrix where all the diagonal elements are the same scalar value. Scalar matrices can be non-singular if the scalar value is non-zero.
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Diagonal Matrix: A matrix in which all off-diagonal elements are zero. Diagonal matrices can be non-singular if all diagonal elements are non-zero.
Thus, for a matrix to have an inverse, it must be non-singular (i.e., its determinant must be non-zero).
The correct option is:
None Singular: Every square non-singular matrix will have an inverse.
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In interpolation is used to represent the δ
Forward difference Δ
Central difference
Backward difference -
In interpolation is used to represent the δ
Forward difference Δ
Central difference
Backward difference@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
In interpolation is used to represent the δ
Forward difference Δ
Central difference
Backward differenceIn interpolation, the notation (\delta) typically represents the forward difference operator.
Explanation:
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Forward Difference (\delta): Used to denote the difference between successive values in a sequence. If ( f(x) ) is a function and ( \delta f(x) ) represents the forward difference, then:
[ \delta f(x) = f(x + h) - f(x) ] -
Backward Difference (\nabla): Represents the difference between preceding values in a sequence. If ( \nabla f(x) ) represents the backward difference, then:
[ \nabla f(x) = f(x) - f(x - h) ] -
Central Difference: Represents the average of the forward and backward differences:
[ \Delta f(x) = \frac{f(x + h) - f(x - h)}{2} ] -
Difference Operator (\Delta): This operator generally represents the forward difference when used in the context of interpolation.
Thus, in interpolation, the symbol (\delta) is used to represent the forward difference.
So the correct option is:
Forward difference (\delta)
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The base of the decimal system is _______
10
0
2
8
None of the above.