MTH603 Mid Term Past and Current Solved Paper Discussion
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An indefinite integral may _________ in the sense that the limit defining it may not exist.
Diverge
Converge -
An indefinite integral may _________ in the sense that the limit defining it may not exist.
Diverge
Converge@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
An indefinite integral may _________ in the sense that the limit defining it may not exist.
Diverge
ConvergeDiverge
Explanation:
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Indefinite Integral: This represents a family of functions whose derivatives are the integrand. While the concept of convergence and divergence more commonly applies to definite integrals, the idea of divergence can apply to indefinite integrals in the context of improper integrals or when dealing with limits.
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Diverge: An integral (definite or indefinite) is said to diverge if it does not converge to a finite value. In the context of indefinite integrals, divergence can occur if the integral involves terms or functions that lead to an unbounded result.
Thus, an indefinite integral may diverge if the limits involved lead to an unbounded or non-existent result.
So, the correct option is:
Diverge
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An improper integral is the limit of a definite integral as an endpoint of the interval
of integration approaches either a specified real number or ∞ or -∞ or, in some cases, as both endpoints approach limits.TRUE
FALSE -
An improper integral is the limit of a definite integral as an endpoint of the interval
of integration approaches either a specified real number or ∞ or -∞ or, in some cases, as both endpoints approach limits.TRUE
FALSE@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
An improper integral is the limit of a definite integral as an endpoint of the interval
of integration approaches either a specified real number or ∞ or -∞ or, in some cases, as both endpoints approach limits.TRUE
FALSETrue
Explanation:
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Improper Integral: An improper integral is a type of integral where one or both of the limits of integration are infinite, or where the integrand has an infinite discontinuity within the interval of integration.
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Definition: Specifically, an improper integral can be defined as the limit of a definite integral where the endpoints of the integration interval approach either a finite value or infinity (∞ or -∞), or as both endpoints approach specific limits.
Therefore, the statement accurately describes the concept of an improper integral.
So, the statement is:
True
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Euler’s Method numerically computes the approximate derivative of a function.
TRUE
FALSE -
@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
Euler’s Method numerically computes the approximate derivative of a function.
TRUE
FALSEFalse
Explanation:
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Euler’s Method: This is a numerical technique for solving ordinary differential equations (ODEs) by approximating the solution at discrete points. It does not compute the derivative directly but instead uses the derivative to update the solution iteratively.
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Derivative Computation: Euler’s Method uses the derivative provided by the differential equation to estimate the next value in the solution. It does not numerically compute or approximate the derivative itself.
Thus, Euler’s Method is used to approximate solutions of differential equations, not to compute the derivative of a function.
So, the statement is:
False
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Euler’s Method numerically computes the approximate ________ of a function.
Antiderivative
Derivative
Error
Value -
Euler’s Method numerically computes the approximate ________ of a function.
Antiderivative
Derivative
Error
Value@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
Euler’s Method numerically computes the approximate ________ of a function.
Antiderivative
Derivative
Error
ValueValue
Explanation:
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Euler’s Method: This numerical technique is used to approximate the solution of an ordinary differential equation by iteratively computing approximate values of the function at discrete points.
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Approximate Value: Euler’s Method estimates the function’s value at successive points based on its derivative, rather than computing the derivative or antiderivative directly.
So, the correct option is:
Value
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If we wanted to find the value of a definite integral with an infinite limit, we can instead replace the infinite limit with a variable, and then take the limit as this variable goes to _________.
Chose the correct option :
Constant
Finite
Infinity Click here for detail
Zero -
If we wanted to find the value of a definite integral with an infinite limit, we can instead replace the infinite limit with a variable, and then take the limit as this variable goes to _________.
Chose the correct option :
Constant
Finite
Infinity Click here for detail
Zero@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
If we wanted to find the value of a definite integral with an infinite limit, we can instead replace the infinite limit with a variable, and then take the limit as this variable goes to _________.
Chose the correct option :
Constant
Finite
Infinity Click here for detail
ZeroInfinity
Explanation:
- Definite Integral with Infinite Limit: When evaluating a definite integral with an infinite limit, such as (\int_{a}^{\infty} f(x) , dx), we replace the infinite limit with a variable (often denoted as (t)) and then evaluate the integral (\int_{a}^{t} f(x) , dx). After integrating, we take the limit of this result as (t) approaches infinity.
So, the correct option is:
Infinity
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The Jacobi iteration ______, if A is strictly diagonally dominant.
Converges
Diverges -
@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
The Jacobi iteration ______, if A is strictly diagonally dominant.
Converges
DivergesConverges
Explanation:
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Jacobi Iteration: This is an iterative method for solving systems of linear equations. The convergence of the Jacobi method depends on the properties of the matrix (A).
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Strict Diagonal Dominance: If matrix (A) is strictly diagonally dominant (i.e., for each row of the matrix, the magnitude of the diagonal entry is greater than the sum of the magnitudes of the other entries in that row), then the Jacobi iteration is guaranteed to converge.
Thus, if (A) is strictly diagonally dominant, the Jacobi iteration converges.
So, the correct option is:
Converges
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By using determinants, we can easily check that the solution of the given system of linear equation exits and it is unique.
TRUE
FALSE -
By using determinants, we can easily check that the solution of the given system of linear equation exits and it is unique.
TRUE
FALSE@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
By using determinants, we can easily check that the solution of the given system of linear equation exits and it is unique.
TRUE
FALSETRUE
Explanation:
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Determinants and Uniqueness: For a system of linear equations (A\mathbf{x} = \mathbf{b}) where (A) is a square matrix, the determinant of (A) helps in determining the existence and uniqueness of the solution.
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Existence: If (\det(A) \neq 0), the matrix (A) is non-singular (invertible), which implies that the system has a unique solution.
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Uniqueness: If (\det(A) = 0), the matrix (A) is singular, and the system either has no solution or has infinitely many solutions, depending on the consistency of the system.
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Thus, by checking the determinant, we can determine if the solution exists and if it is unique.
So, the statement is:
TRUE
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The absolute value of a determinant (|detA|) is the product of the absolute values of the eigenvalues of matrix A
TRUE
FALSE -
The absolute value of a determinant (|detA|) is the product of the absolute values of the eigenvalues of matrix A
TRUE
FALSE@zaasmi said in MTH603 Mid Term Past and Current Solved Paper Discussion:
The absolute value of a determinant (|detA|) is the product of the absolute values of the eigenvalues of matrix A
TRUE
FALSETRUE
Explanation:
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Determinant and Eigenvalues: For a square matrix (A), the determinant of (A) is equal to the product of its eigenvalues, considering their algebraic multiplicities.
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Absolute Values: The absolute value of the determinant (|\det(A)|) is indeed equal to the product of the absolute values of the eigenvalues of (A).
So, the statement is:
TRUE
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