In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be
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In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be
Answer
$\frac{\pi}{2}$
$\pi$
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In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be
Answer
$\frac{\pi}{2}$
$\pi$
$\frac{\pi}{8}$@zaasmi said in In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be:
In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be
Answer
$\frac{\pi}{2}$
$\pi$
$\frac{\pi}{8}$To determine the width of each interval for the integral \int_{0}^{\frac{\pi}{2}} \cos x , dx  by dividing the interval into four equal parts, we use the formula:
h = \frac{b - a}{n}
where:
• a = 0, • b = \frac{\pi}{2}, • n = 4.Calculating h:
h = \frac{\frac{\pi}{2} - 0}{4} = \frac{\frac{\pi}{2}}{4} = \frac{\pi}{8}
So, the width of the interval should be \frac{\pi}{8} .
Thus, the correct answer is \frac{\pi}{8} .
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